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A college intramural four-man basketball team is trying to choose its starting line-up from a six-man roster so as to maximize total height over 56.

A college intramural four-man basketball team is trying to choose its starting line-up from a six-man roster so as to maximize total height over 56. The roster follows:

Player

Position

Height in inches over 5 6

A - ALEX

Center

10

B - BRYAN

Center

9

C - CHARLES

Forward

6

D - DAVE

Forward

6

E - EDGAR

Guard

4

F - FRANK

Guard

-1

The starting line-up must satisfy the following constraints: (i) At least one center should start. (ii) Either Alex or Frank must be held in reserve. (iii) Only one guard must start. (iv) If Charles starts, then Edgar cannot start.

1. Which represents constraint (i)

Choices:

a. NIC (not in choices)

b. A <= B

c. A+ F =1

d. E <= F

e. Bryan, Dave, Edgar, Frank

f. A + B = 1

g. C + E <=1

h. Alex, Bryan, Dave, Edgar

i. A + F <= 1

j. A + B > = 1

k. E + F = 1

l. Bryan, Charles, Edgar , Frank

m. C + E = 1

n. C <= E

o. E + F <= 1

2. Which represents constrain (ii)

Choices:

a. NIC (not in choices)

b. A <= B

c. A+ F =1

d. E <= F

e. Bryan, Dave, Edgar, Frank

f. A + B = 1

g. C + E <=1

h. Alex, Bryan, Dave, Edgar

i. A + F <= 1

j. A + B > = 1

k. E + F = 1

l. Bryan, Charles, Edgar , Frank

m. C + E = 1

n. C <= E

o. E + F <= 1

3. Which represents contraint (iii)

Choices:

a. NIC (not in choices)

b. A <= B

c. A+ F =1

d. E <= F

e. Bryan, Dave, Edgar, Frank

f. A + B = 1

g. C + E <=1

h. Alex, Bryan, Dave, Edgar

i. A + F <= 1

j. A + B > = 1

k. E + F = 1

l. Bryan, Charles, Edgar , Frank

m. C + E = 1

n. C <= E

o. E + F <= 1

4. Which represents constrain ( iv)

Choices:

a. NIC (not in choices)

b. A <= B

c. A+ F =1

d. E <= F

e. Bryan, Dave, Edgar, Frank

f. A + B = 1

g. C + E <=1

h. Alex, Bryan, Dave, Edgar

i. A + F <= 1

j. A + B > = 1

k. E + F = 1

l. Bryan, Charles, Edgar , Frank

m. C + E = 1

n. C <= E

o. E + F <= 1

5. Players in the starting line-up

Choices:

a. NIC (not in choices)

b. A <= B

c. A+ F =1

d. E <= F

e. Bryan, Dave, Edgar, Frank

f. A + B = 1

g. C + E <=1

h. Alex, Bryan, Dave, Edgar

i. A + F <= 1

j. A + B > = 1

k. E + F = 1

l. Bryan, Charles, Edgar , Frank

m. C + E = 1

n. C <= E

o. E + F <= 1

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