Question
A computer uses an 8-bit floating-point representation consistent with IEEE 754 normalized format. It is identical to the 32-bit and 64-bit formats in terms of
A computer uses an 8-bit floating-point representation consistent with IEEE 754 normalized format. It is identical to the 32-bit and 64-bit formats in terms of the meaning of fields and special encodings. The format includes 1 sign bit, 4 exponent bits, and 3 mantissa (magnitude or fraction) bits. As in IEEE 754, 0000 and 1111 in exponent field are reserved.The exponent field employs an excess-7 coding.
The following table gives the 8-bit Excess-7 representation.
Decimal | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
Unsigned | 0000 | 0001 | 0010 | 0011 | 0100 | 0101 | 0110 | 0111 |
Excess-7 | Reserved | -6 | -5 | -4 | -3 | -2 | -1 | 0 |
Decimal | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 |
Unsigned | 1000 | 1001 | 1010 | 1011 | 1100 | 1101 | 1110 | 1111 |
Excess-7 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | reserved |
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[Help: in normal binary representation 240 = 111100002 = 1.111 * 27 and 15.5 = 1111.12 = 1.1111 * 23]
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What is 01001000 in this representation?
a.1
b.2
c.3
d.4
If x = - 2, how x will be represented?
a.11000000
b.01000000
c.10000010
d.11111110
What is the largest number in this representation, and how it will be represented?
a.11111111 = 155
b.01101111 = 15.5
c.01110111 = 240
d.00111111 = 240
What is the third largest number in this representation, and how it will be represented??
a.11111101 = 153
b.01111101 = 14.5
c.01110101 = 237
d.01110101 = 208
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