Question
a) Consider a computer that has a physical address space of 256MB. The page size is 1KB and the virtual address space is 1GB (230B).
a) Consider a computer that has a physical address space of 256MB. The page size is 1KB and the virtual address space is 1GB (230B). How many bits of each virtual address is the virtual page number? How many bits of each physical address is the physical page frame number? b) Assume a virtual memory system has 4KB page size and 32-bit virtual address. The page table is a linear page table with 4B page table entry (PTE) and the page table base register (PTBR) is 0x00000800, which points to the page table in the memory for this current process. Given the virtual address 0x00A942F0, what is the corresponding address of the page table entry in the physical memory?
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