A container of water has a cross sectional area of A = 0.35 m . A piston sits on top of the water. There is a spout located 0.15 m from the bottom of the tank, open to the atmosphere, and a stream of water exits the spout. The cross sectional area of the spout is As = 6.0 x 10 4 m . Ignore all friction and dissipative forces. 20 kg 0.5 m p = 1000- m 3 0.15 m Image Description a. What is the velocity of the water as it leaves the spout? U = m/s b. If the opening of the spout is located 1.7 m above the ground, how far from the spout does the water hit the floor? Ax = m