Question
A cube with 100 dimensions 2 base cells: (a1, a2, ., a100 , count), (b1, b2, , b100 , count) Why is the amount of
A cube with 100 dimensions 2 base cells: (a1, a2, ., a100 , count), (b1, b2, , b100 , count)
Why is the amount of aggregate cells for having count >= 2 equal to 4, shouldn't it be 0 since you subtract out the overlapping cells? Please explain why it is not 0.
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Constraint Databases And Applications Esprit Wg Contessa Workshop Friedrichshafen Germany September 1995 Proceedings Lncs 1034
Authors: Gabriel Kuper ,Mark Wallace
1st Edition
3540607943, 978-3540607946
