A data set includes the counts of chocolate chips from three different types of Chips Ahoy cookies. The accompanying StatCrunch display shows results from analysis of variance used with those three types of cookies. Use a

0.05

significance level to test the claim that the three different types of cookies have the same mean number of chocolate chips.

ANOVA table
Source	DF	SS	MS	F-Stat	P-value
Columns	2	1087.9500	543.97500	57.2475	<0.0001
Error	77	731.66667	9.5021645
Total	79	1819.6167

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Part 1

Determine the null hypothesis.

H0:

mu 1 equals mu 2 equals mu 31=2=3

At least one of the means is different from the others

Atleastoneofthemeansisdifferentfromtheothers

All of the means are different

Allofthemeansaredifferent

mu 1 less than mu 2 less than mu 31<2<3

mu 1 greater than mu 2 greater than mu 31>2>3

Part 2

Determine the alternative hypothesis.

H1:

mu 1 equals mu 2 equals mu 31=2=3

mu 1 greater than mu 2 greater than mu 31>2>3

mu 1 less than mu 2 less than mu 31<2<3

At least one of the means is different from the others

Atleastoneofthemeansisdifferentfromtheothers

All of the means are differentAllofthemeansaredifferent

Part 3

Determine the test statistic.

The test statistic is

enter your response here.

(Round to two decimal places as needed.)

Part 4

Determine the P-value.

The P-value is

enter your response here.

(Round to three decimal places as needed.)

Part 5

What can you conclude?

There

is

is not

sufficient evidence at a

0.05

significance level to warrant rejection of the claim that the three different types of chocolate chip cookies have

different

the same

mean number of chocolate chips.