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A distribution of values is normal with a mean of 1 1 3 1 . 2 and a standard deviation of 2 9 . 7

A distribution of values is normal with a mean of 1131.2 and a standard deviation of 29.7.
Find the probability that a randomly selected value is greater than 1047.1.
P(X >1047.1)=
Enter your answer as a number accurate to 4 decimal places. *Note: all z-scores must be rounded to the nearest hundredth.

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