You are an engineer in a manufacturing plant. Your company will procure an important equip- ment that will contain and heat 100 moles of ammonia gas. The initial condition of the ammo- nia gas will be at 15 atm and 300 liters. The ammonia gas will then be heated until it expands to 500 liters while maintaining the 15 atm pressure. For this, a meeting with the accounting department is to be facilitated to talk about the cost of the said equipment. A teammate of yours, an engineer and a previous classmate of yours, made his/her computa- tions regarding the cost. You've found out that his/her computations are "ideal" that: (1) he/she used specific heat capacities intended only for 25 C and 100 kpa conditions and (2) he/she used ideal gas law. From your extensive training in engineering school, you know that (1) specific heat capacity varies with temperature and (2) instead of using ideal gas law, it is more realistic to use "real gas law" such as Van Der Waals equation (see presented formula). According to a research made by the RnD (Research and Development) department of your company, for every positive increase in the change of entropy in the process (of the equip- ment to be procured), the cost accounts for 300.00 Php. Thus, 1 J/K increase in entropy in the process of the said equipment corresponds to 300.00 Php; and 2 J/K increase corresponds to 600.00 Php. Save your workmate from his/her impending trouble by showing him/her the difference be- tween the cost he/she computed (ideal) and yours (realistic) in Php. Should your workmate present his/her computations, the accounting department will process the release of the financing of the equipment (which could take some time - profitability re- views, signatories of various bosses, etc.). Once the money is released, it would be a lot trouble if what he/she requested is way below what it is supposed to be. For the Van Der Waal's equation: P = atm n = mol V = L T = K For ammonia with respect to the Van Der Waal's equation: a = 4.225 L/mol b = 0.03713 L/mol Formula to convert Celsius to Kelvin is given by: K = C +273.15 Answer Format: [2 decimals] 1.23 12.34 123.34 1,234.56 123,456.78 0.12 0.10 1.00 (10 Points) (P + na) (V nb) = nRT