A Ferris wheel has a radius of 20 n1. Passengers get on halvay up on the right side. The direction of rotation is counter clockwise. The bottom of the Ferris wheel is 2 m off the ground. It rotates every 36 seconds. The equation of the function is 2m Mr) 2 20 sing + 22 , where 51.1?) is the height of a rider, r seconds after leaving a ramp halfway up of the Ferris wheel. Show the graph of this mction in an appropriate window on the T184 calculator for two revolutions of the wheel. For how many seconds would a rider be above the height of 38 meters for the two revolutions? Determine the rider's height above the ground after 15 seconds. How long would it take to complete two revolutions? 3 marks Total amount of time when height is above 38 m for 2 revolutions: 2 marks Height above ground after 15 s. I mark Time to complete one revolution: I mark