A fighter jet takes off from the horizontal deck of an aircraft carrier. Starting from rest, it
Question:
A fighter jet takes off from the horizontal deck of an aircraft carrier. Starting from rest, it achieves a speed of 58.1m/s as it travels 81.5m along the deck to the end of the runway. As it leaves the deck, its acceleration changes to 4.37m/s2 at an angle of 48.8 above horizontal.
25% Part (a) What is the magnitude, in meters per squared second, of the acceleration of the jet as it accelerates along the deck? a11 = 20.7120.71 m/s2 Correct!
25% Part (b) What is the speed, in meters per second, of the jet 5.09s after it leaves the deck of the aircraft carrier? v =
25% Part (c) What is the altitude of the jet, in meters above the deck, 5.09s after it leaves the end of the deck of the aircraft carrier? h =
25% Part (d) What horizontal distance, in meters, is the jet from the end of the runway 5.09s after it leaves the deck of the aircraft carrier?
d =