A fish farm in Maine holds 200,000 fish. The natural growth rate is 15% (assume continuous growth) per year. The owner harvests 30,000 fish (uniformly spread out) each year. Set up a differential equation modeling the fish population as a function of time. dN OA. dt -0.15/ - 200000 dN OB. dt - =0.15N| 1- N 200000 NP Oc. dt = 0.15N N OD. dt dN = 0.15N 1 200000 - 30000 OCT 8