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a) for every irrational number rQ (set of irrationals) there is a sequence of rational numbers that converges to r: (b) If y > 0;
a) for every irrational number rQ
(set of irrationals) there is a sequence
of rational numbers that converges to r:
(b) If y > 0; show that there exists an n N such that
1/3^n< y:
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