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a. For the input 1111111000000011, the RLE would be 7,1,8,2. This is because there are seven consecutive 1s, followed by one 0, then eight consecutive
a. For the input 1111111000000011, the RLE would be 7,1,8,2. This is because there are seven consecutive 1s, followed by one 0, then eight consecutive 0s, and finally two 1s. b. For the input 1111100000000000, the RLE would be 5,1,10,0. This is because there are five consecutive 1s, followed by one 0, and then ten consecutive 0s. The final 0 indicates that there are no more 1s following the last run of 0s. c. For the input 1010101010101010, the RLE would be 1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1. This is because the 1s and 0s alternate without any runs of consecutive identical digits
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