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( a ) For the purpose of this question, consider a vertex rearranging function for a graph G = ( V , E ) is
a
For the purpose of this question, consider a "vertex rearranging function" for a graph G V E is a function phi : V V that rearranges the vertices of G while preserving the graph's structure. This means that if there is an edge between vertices u and v in G then there must also be an edge between phi u and phi v in G and if there is no edge between u and v then there is none between phi u and phi v In other words, phi is a bijective map from V to V such that uv in E implies phi uphi v in E and uv E implies phi uphi v E
Show that the graph G shown in the stimulus on the left only has one possible nontrivial that doesn't simply map each vertex to itself 'vertex rearranging function' as defined above.b
How many colourings does the graph from part a have? Hint: there are at least
Justify your answer though partial marks are available for correct answers without justificationc
We are given possible colourings of our graph G from part ashown in the stimulus on the left
Find another possible colouring.d
Consider an arbirary graph G V E where V is the set of vertices and E is the set of edges. Let C be a set of colours.
Let ColG be the set of all colourings of vertices of G by colours from C That is
ColG alpha :V C such that alpha is a valid colouring of G
Define a relation R ColG times ColG as follows:
alpha beta in R if and only if there exists a bijection f:CC such that for all v in V falpha vbeta v
Prove that R is an equivalence relation.We say two colourings alpha : VC and beta : V C are equivalent under permutation of colours if alpha beta in Re
With ColG as defined in d define the relation R ColG times ColG as follows:
alpha beta in R if and only if there exists a vertex rearrangement function see a
phi : V V such that for all v in Valpha vbeta phi v
This is to say, one coloring can be transformed into the other by rearranging the vertices according to phi while keeping the colors assigned to each vertex the same.
Prove that R is an equivalence relation.f
Consider the colourings AH of the graph from part a shown on the left.
Draw the directed graph with
vertices are these colourings do not include the extra one you found in c; and
edges are given by the relation Rg
Consider the colourings AH of the graph from part a shown on the left.
Draw the directed graph with
vertices are these colourings do not include the extra one you found in c; and
edges are given by the relation Rh
How do R and R partition the set of colourings A H respectively?i
Consider the directed graph obtained by associating each vertex to a colouring and adding an edge between two vertices alpha and beta if alpha beta in Rcup R
We define two colourings alpha and beta as being distinct when there does not exist a path between alpha and beta on said graph.
How many colourings in AH are distinct?
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