Answered step by step
Verified Expert Solution
Link Copied!

Question

1 Approved Answer

( a ) For the purpose of this question, consider a vertex rearranging function for a graph G = ( V , E ) is

(a)
For the purpose of this question, consider a "vertex rearranging function" for a graph G =(V, E) is a function \phi : V -> V that rearranges the vertices of G while preserving the graph's structure. This means that if there is an edge between vertices u and v in G, then there must also be an edge between \phi (u) and \phi (v) in G, and if there is no edge between u and v, then there is none between \phi (u) and \phi (v). In other words, \phi is a bijective map from V to V such that (u,v) in E implies (\phi (u),\phi (v)) in E and (u,v) E implies (\phi (u),\phi (v)) E.
Show that the graph G =({1,2,3,4},{{1,2},{2,3},{1,3},{3,4}})(shown in the stimulus on the left) only has one possible non-trivial (that doesn't simply map each vertex to itself) 'vertex rearranging function' as defined above.(b)
How many 3-colourings does the graph from part (a) have? (Hint: there are at least 8)
Justify your answer (though partial marks are available for correct answers without justification)(c)
We are given 8 possible 3-colourings of our graph G from part (a).(shown in the stimulus on the left).
Find another possible 3-colouring.(d)
Consider an arbirary graph G =(V, E) where V is the set of vertices and E is the set of edges. Let C be a set of colours.
Let ColG be the set of all colourings of vertices of G by colours from C. That is,
ColG ={\alpha :V -> C such that \alpha is a valid colouring of G }
Define a relation R1 ColG \times ColG as follows:
(\alpha ,\beta ) in R1 if and only if there exists a bijection f:C->C such that for all v in V, f(\alpha (v))=\beta (v)
Prove that R1 is an equivalence relation.We say two colourings \alpha : V->C and \beta : V -> C are equivalent under permutation of colours if (\alpha ,\beta ) in R1.(e)
With ColG as defined in (d), define the relation R2 ColG \times ColG as follows:
(\alpha ,\beta ) in R2 if and only if there exists a vertex rearrangement function (see (a))
\phi : V -> V such that for all v in V,\alpha (v)=\beta (\phi (v)).
This is to say, one coloring can be transformed into the other by rearranging the vertices according to \phi while keeping the colors assigned to each vertex the same.
Prove that R2 is an equivalence relation.(f)
Consider the 8 colourings (A-H) of the graph from part (a) shown on the left.
Draw the directed graph with
vertices are these 8 colourings (do not include the extra one you found in (c)); and
edges are given by the relation R1.(g)
Consider the 8 colourings (A-H) of the graph from part (a) shown on the left.
Draw the directed graph with
vertices are these 8 colourings (do not include the extra one you found in (c)); and
edges are given by the relation R2.(h)
How do R and R partition the set of colourings {A,..., H} respectively?(i)
Consider the directed graph obtained by associating each vertex to a colouring and adding an edge between two vertices \alpha and \beta if (\alpha ,\beta ) in R\cup R.
We define two colourings \alpha and \beta as being distinct when there does not exist a path between \alpha and \beta on said graph.
How many colourings in A-H are distinct?
image text in transcribed

Step by Step Solution

There are 3 Steps involved in it

Step: 1

blur-text-image

Get Instant Access to Expert-Tailored Solutions

See step-by-step solutions with expert insights and AI powered tools for academic success

Step: 2

blur-text-image

Step: 3

blur-text-image

Ace Your Homework with AI

Get the answers you need in no time with our AI-driven, step-by-step assistance

Get Started

Recommended Textbook for

Database Concepts

Authors: David M Kroenke, David J Auer

6th Edition

0132742926, 978-0132742924

More Books

Students also viewed these Databases questions