A force F applied to an object of mass m, produces an acceleration of 3.90 m/s". The same force applied to a second object of mass my produces an acceleration of 1.50 m/s. (a) What is the value of the ratio m1/m2? (b) If m, and my are combined into one object, find its acceleration under the action of the force F. m/ s2Two forces F , and F 2 act on a 2.40-kg object. F1 = 40.0 N and F2 = 14.0 N. F 2 90.0 60.0 m -F m a b (a) Find the acceleration of the object for the configuration of forces shown in Figure (a). magnitude m/s2 direction . (counterclockwise from F 1) (b) Find the acceleration of the object for the configuration of forces shown in Figure (b). magnitude m/s direction . (counterclockwise from F )The systems shown below are in equilibrium with m = 8.90 kg and 0 = 34.0. If the spring scales are calibrated in newtons, what do they read? Ignore the masses of the pulleys and strings and assume the pulleys and the incline are frictionless. m m m a b m m m C d scale in (a): N scale in (b): IN scale in (c): N scale in (d): INAssume the three blocks (m, = 1.0 kg, m2 = 2.0 kg, and m3 = 4.0 kg) portrayed in the figure below move on a frictionless surface and a force F = 38 N acts as shown on the 4.0 kg block. F (a) Determine the acceleration given this system (in m/s to the right). m/s2 (to the right) (b) Determine the tension in the cord connecting the 4.0 kg and the 1.0 kg blocks (in N). N (c) Determine the force exerted by the 1.0 kg block on the 2.0 kg block (in N). (d) What If? How would your answers to parts (a) and (b) of this problem change if the 2.0 kg block was now stacked on top of the 1.0 kg block? Assume that the 2.0 kg block sticks to and does not slide on the 1.0 kg block when the system is accelerated. (Enter the acceleration in m/s