A fruit-packing company produced peaches last summer whose weights were normally distributed with mean 14 ounces and standard deviation 0.8 ounce. Among a sample of 1000 of those peaches, about how many could be expected to have weights of at least 14 ounces? Click here to see page 1 of the table for areas under the standard normal curve. Click here to see page 2 of the table for areas under the standard normal curve. The number of peaches expected to have weights of at least 14 ounces is. Round to the nearest whole number as needed.)A fruit-packing company produced peaches last summer whose weights were normally distriouted with mean 14 ounces and standard deviation 0.6 ounce. Among a sample of 1000 of those peaches, about how many could be expected to have weights between 14.3 and 14.9 ounces? Click here to see page 1 of the table for areas under the standard normal curve. Click here to see page 2 of the table for areas under the standard normal curve. The number of peaches expected to have weights between 14.2 and 14.9 ounces is (Round to the nearest whole number as needed ) Find the z-score that best satisfies the condition. 14% of the total area is to the left of 2. z= (Round to the nearest hundredth.) Find the value of z such that 68.4% of the total area is to the left of z. Click to view the areas under the Standard Normal Curve. Round to two decimal places as needed.)The mean of a normally distributed data set is 74 with a standard deviation of 5. Find the data values that is greater than 6% of the data. Click here to see page 1 of the fahle for areas under the standard normal curve. Click here to see page 2 of the table for areas under the standard normal curve. The data value that is greater than 6% of the data is |:| (Round to the nearest whole number as needed.)