A genetic experiment involving peas yielded one sample of offspring consisting of 404 green peas and 148 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 27% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses? O A. Ho: p # 0.27 O B. Ho: p = 0.27 H1: p= 0.27 H1: p 0.27 O E. Ho: P# 0.27 OF. Ho: P# 0.27 H1 : p > 0.27 H1: p = 0.27Formulate the indicated conclusion in nontechnical terms. Be sure to address the original claim. The owner of a football team claims that the average attendance at games is over 523, and he is therefore justified in moving the team to a city with a larger stadium. Assuming that a hypothesis test of the claim has been conducted and that the conclusion is failure to reject the null hypothesis, state the conclusion in nontechnical terms. O A. There is not sufficient evidence to support the claim that the mean attendance is greater than 523. O B. There is sufficient evidence to support the claim that the mean attendance is less than 523 O C. There is not sufficient evidence to support the claim that the mean attendance is less than 523. O D. There is sufficient evidence to support the claim that the mean attendance is greater than 523.In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6964 subjects randomly selected from an online group involved with ears. There were 1332 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis. OA. Ho : p = 0.2 O B. Ho: P # 0.2 H1: p > 0.2 H1 : p = 0.2 O C. Ho: p= 0.2 OD. Ho: P> 0.2 H1: p