A host ID of all ones is called the

address

a$.$ Multicast

b$.$ Broadcast

c$.$ Simulcast

d$.$ Gateway

For the CIDR prefix length of $\frac{?}{18},$ the subnet mask will be

a$.255\mathrm{.}255\mathrm{.}128\mathrm{.}0$

b$.255\mathrm{.}255\mathrm{.}192\mathrm{.}0$

c$.255\mathrm{.}255\mathrm{.}0\mathrm{.}192$

d$.255\mathrm{.}255\mathrm{.}255\mathrm{.}0$

For the CIDR prefix length of $\frac{?}{25},$ there are

host addresses

a$.27$

b$.32$

c$.128$

d$.96$

For the CIDR prefix length of $\frac{?}{16},$ the number of host addresses available is equivalent to

class B network$($s$)$

a$.1$

b$.2$

c$.4$

d$.8$

A certain company contains $2$ divisions, each on its own subnet and each requires between $30$ and $35$

hosts. Use this information to answer questions $21$ and $22$ below:

For a class C address, is the subnet mask $255\mathrm{.}255\mathrm{.}255\mathrm{.}224$ suitable?

a$.$ Yes

b$.$ No

Inspect the following subnets and determine which of them is suitable for this case:

a$.255\mathrm{.}255\mathrm{.}255\mathrm{.}224$

b$.255\mathrm{.}255\mathrm{.}255\mathrm{.}128$

c$.255\mathrm{.}255\mathrm{.}255\mathrm{.}192$

d$.$ None of the above

If we assume we have $100$ stores that are expected to expand by $4$ stores$/$year$.$ Assume we want to

design a network that suites our needs for the next $5$ years. Each store requires exactly $4$ IPs. If the IP

address is $165\mathrm{.}32\mathrm{.}0\mathrm{.}0.$ Use this information to answer questions $23-26$ below:

What class is this IP address?

a$.$ A

b$.$ B

c$.$ C

d$.$ D

What is the total number of hosts that your network should support for the whole network for the

whole period, assuming that each store requires $1$ IP for the router and the rest for hosts?

a$.40$

b$.360$

c$.480$

d$.180$

What is the required subnet mask?

a$.255\mathrm{.}255\mathrm{.}240\mathrm{.}0$

b$.255\mathrm{.}255\mathrm{.}255\mathrm{.}0$

c$.255\mathrm{.}255\mathrm{.}127\mathrm{.}0$

d$.$ None of the above

What is the total number of routers?

a$.120$

b$.1$

c$.32$

d$.64$