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A hydrocyclone with diameter of 0 . 9 0 0 m is used to classify a minerals slurry at a feed flow rate of 7

A hydrocyclone with diameter of 0.900m is used to classify a minerals slurry at a feed flow rate of 75.6m3 per hour and the volumetric split S is 0.74. The Plitt model was used to evaluate the performance of the hydrocyclone. The simplified equations for the Plitt model are among the equations given in the formulae sheet.
(Note: The flow rate for the Plitt model is in litres/min and the cyclone diameter is in cm). The size distribution of the feed is given Table 1 and if required assume the specific gravity of solids to be 3.2 and that of slurry (pulp) to be 1.455. The sharpness of separation for of the cyclone m=2.5.
Using the Plitt model and feed size distribution data determine (show sample calculations for the row involving 53 micrometres size data):
a) the d50c and Rf for the cyclone
4
b) the actual, corrected, and reduced partition numbers for the cyclone
9
c) If the two feed size distributions labelled (A) and (B) are used what difference would you expect in the d50c from Plitt model and why?
3
d) Name four ways in which you could improve the efficiency of the hydrocyclone.
4
Table 1: Design data set for 0.900m cyclone
\table[[\table[[Size,],[Micrometers]],\table[[Feed size distribution,],[% retained (A)]],\table[[Feed size distribution,],[% retained (B)]]],[212,2,1.4],[150,12.4,6.8],[106,22.3,13.8],[75,25,28.5],[53,16.1,21.1],[38,10.6,12.6],[25,5.5,7.5],[0,6.1,8.3]]
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