A ladder $10ft$ long rests against a vertical wall. If the bottom of the ladder slides away from the wall at a rate of $1\mathrm{.}1f\frac{t}{s},$ how fast $($in rad$/$s$)$ is the angle $($in radians$)$ between the ladder and the ground changing when the bottom of the ladder is $8ft$ from the wall? $($That is$,$ find the angle's rate of change when the bottom of the ladder is $8ft$ from the wall.$)$

$ra\frac{d}{s}$