A LaGuardia Physics Professor drops a stone into a well. How deep is the well if the Professor hears the sound from the stone hitting the bottom of the well 1.9 5 later? Neglect the air resistance and take the free fall acceleration g = 9.81 m/sz. The air temperature is T = 245C. Hint: g - if 2 ; (2) for the sound to travel back to the surface, h : c - t2; and (3) for the delay time, t : t1 l 752. You have 3 equations and 3 unknown variables: 151,752, and h. And, of course, you will need the speed of sound at the given air temperature: c = (331.3 + 0.606 ~ T) m/s. Try to set the following equations: (1) for the stone to fall down, h = The depth of the well, h = Units m v V . How long did it take for the sound to travel back? The time, ts = Units