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a. log (alpha) b. log (alpha +1) c. 1/1 + alpha d. X^ alpha Given that a > 0 and value of integral at a

a. log (alpha)

b. log (alpha +1)

c. 1/1 + alpha

d. X^ alpha

Given that a > 0 and value of integral at a = 0 is 0. xa-1 The value of S - dx is logx

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