Question
a. log (alpha) b. log (alpha +1) c. 1/1 + alpha d. X^ alpha Given that a > 0 and value of integral at a
a. log (alpha)
b. log (alpha +1)
c. 1/1 + alpha
d. X^ alpha
Given that a > 0 and value of integral at a = 0 is 0. xa-1 The value of S - dx is logx
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