A long reach of a wide-rectangular river channel is to be analyzed. There is an underflow sluice gate in the middle of the reach. Table 1 lists many possible scenarios that can be analyzed depending on flow rate, bed roughness and boundary conditions. You have been assigned one of these possible scenarios. Use the fifth digit of your student ID to select the assigned scenario. 5 0 D O LA N Answer following questions. 1. Decide the slope type of the channel. Clearly present your argument, calculations, and interim results that helped to achieve the final answer. No marks will be given if only the final answer is provided. 2. Considering the allocated boundary conditions and the gate at middle of the channel, a. indicate all possible flow changing locations, b. draw flow profile variation along the channel and c. identify/name profile type in each segment. 3. Calculate approximate length of the allocated non-uniform flow profile using direct step method in two steps. Present all your assumptions, approximations, and interim results (to four decimal places) along with the calculations and working-out in each step. Table 1: Preliminary data for question 2 ID 0 1 2 3 4 5 6 00 Bed slope 8 0.001 0.003 0.003 0.008 0.08 7 0.003 approximations, calculations and working-out in each step. 0.08 0.008 0.025 0.002 Manning's roughness 9 0.002 0.025 0.015 0.015 0.025 0.04 0.04 0.04 0.04 0.025 Specific discharge (m/s/m) 4 4 5 6 6 7 7 8 9 9 Starting boundary condition Free Reservoir Reservoir Reservoir Reservoir Reservoir Reservoir Free flowing Free flowing Free flowing Ending boundary condition Reservoir with water level below the channel bed level Free flowing Free flowing Free flowing Free flowing Free flowing Free flowing Reservoir with water level below the channel bed level Reservoir with water level below the channel bed level Reservoir with water level below the channel bed level Non-uniform flow Profile from the start First First second second First Third Third second second Third dv (m) 0.3 0.4 0.5 0.5 0.4 0.3 0.3 0.4 0.3 0.5