Question
A major leaguer hits a baseball so that it leaves the bat at a speed of 30.5 m/s and at an angle of 35.8 degree
A major leaguer hits a baseball so that it leaves the bat at a speed of 30.5 m/s and at an angle of 35.8 degree above the horizontal. You can ignore air resistance.
1.) At what two times is the baseball at a height of 10.2 m above the point at which it left the bat?
2.) Calculate the vertical component of the baseball's velocity at the earlier of the two times calculated in part (1). Assume that UP is the positive vertical direction.
3.) Calculate the horizontal component of the baseball's velocity at the later of the two times calculated in part (1).
4.) Calculate the vertical component of the baseball's velocity at the later of the two times calculated in part (1). Assume that UP is the positive vertical direction.
5.) What is the magnitude of the baseball's velocity when it returns to the level at which it left the bat?
6.) What is the direction of the baseball's velocity when it returns to the level at which it left the bat?
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