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A mole of X reacts at a constant pressure of 43.6 bar via the reaction X(g)+4Y(g)2Z(g), H=75.0 kJ mol1 Before the reaction, the volume of
A mole of X reacts at a constant pressure of 43.6 bar via the reaction X(g)+4Y(g)2Z(g), H=75.0 kJ mol1
Before the reaction, the volume of the gaseous mixture was 5.00 L . After the reaction, the volume was 2.00 L .
Calculate the value of the total energy change, U , in kJ mol1 .
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