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A new production system for a factory is to be purchased and installed for $114,666. This system will save approximately 300,000 kWh of electric power

  1. A new production system for a factory is to be purchased and installed for $114,666. This system will save approximately 300,000 kWh of electric power each year for a 6-year period. Assume the cost of electricity is $0.10 per kWh, and factory MARR is 15% per year, and the salvage value of the system will be $8,666 at year 6. Using the AW method to analyzes if this investment is economically justified

A. calculate the AW of the above investment and insert the result below.

B. Based on the AW value you got in the previous question, is this investment economically justified or not? type you explanation below

  1. A. For the below ME alternatives , which machine should be selected based on the AW analysis. MARR=10%

Machine A

Machine B

Machine C

First cost, $

17,311

30000

10000

Annual cost, $/year

9,377

6,000

4,000

Salvage value, $

4,000

5,000

1,000

Life, years

3

6

2

AW for machine A=

B. For the below ME alternatives , which machine should be selected based on the AW analysis. MARR=10%

Machine A

Machine B

Machine C

First cost, $

15000

23,182

10000

Annual cost, $/year

8,775

6,000

4,000

Salvage value, $

4,000

5,000

1,000

Life, years

3

6

2

AW for machine B=

C. For the below ME alternatives, which machine should be selected based on the AW analysis. MARR=10%.

Machine A

Machine B

Machine C

First cost, $

15000

30000

14,534

Annual cost, $/year

17,872

6,000

4,000

Salvage value, $

4,000

5,000

1,000

Life, years

3

6

2

AW for machine C =

D. Based on the AW value you got in the previous 3 questions, which machine we should select? type you an explanation below

  1. A. for the below two machines and based on AW analysis which machine we should select? MARR=10%.

Machine A

Machine B

First cost, $

27,933

100,000

Annual cost, $/year

10,943

7,000

Salvage value, $

5,730

-

Life, years

3

infinite

the AW for machine A=

B. For th below two machines and based on AW analysis which machine we should select? MARR=10%

Machine A

Machine B

First cost, $

23,260

145,907

Annual cost, $/year

14,596

9,899

Salvage value, $

6,579

-

Life, years

3

infinite

the AW for machine B=

C. Based on the AW value you got in the previous 2 questions, which machine we should select? type you an explanation below

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