A new study on the widely used antidepressant AD+ has been published. The study has information on the side effects of the drug. For each of the 19 randomly chosen users of AD+ who participated in the study, a score from 0 to 100 was assigned according to the severity and variety of side effects from the drug (a score of 0 meant no side effects). A similar assessment was made for 24 independently and randomly chosen users of the competitor antidepressant XAD24. The data are summarized in the following table. Could not fit part e in the picture but the question is : Can we conclude that the variance of scores for all AD+ users is different from the variance of scores for all XAD24 users? Yes or no. Also please include the degree of value for the test statistic - types of test statistics are Z, t, chi-squared and F

V AD+ users XAD24 users x = 49.7 x7 =54.9 $7 = 187.69 $5 = 424.36 (The first row gives the sample means and the second row gives the sample variances.) Assume that the populations of side effect scores for each of the drugs are approximately normally distributed. Can we conclude, at the 0.05 significance level, that the variance of scores for all AD+ users, 6, is different from the variance of scores for all XAD24 users, 67? Perform a two-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places, and round your answers as specified below. (If necessary, consult a list of formulas.) (a) State the null hypothesis Ho and the alternative hypothesis H. H O P Ho : 0 X S H : (b) Determine the type of test statistic to use. (Choose one) 0-0 050 020 (c) Find the value of the test statistic. (Round to three or more decimal places.) 00 X (d) Find the two critical values at the 0.05 level of significance. (Round to three or more decimal places.) and