A nice characteristic of this problem is that it can be developed in small pieces. Remember:

always try to break a problem into smaller pieces that are easier to solve.

b$)$ First write a program that prompts for an integer, displays the integer, and stops asking for more

integers when $0$ is entered. Use while. Under what condition do you continue to loop? Here is a

suggested outline:

prompt for an integer # $($and convert the string to an int$)$

while some$\_$Boolean$\_$condition:

# do something

prompt for another integer

c$)$ Once that simple program is tested and working, add in another piece such as $($c$)$ to count the

number of odd integers entered. Create a variable with an appropriate name, such as

odd$\_$count, and assign it an initial value of $0($before the while loop$).$ When an odd number is

entered, add one to odd$\_$count $($for example, odd$\_$count $+=1).$ Display the count.

d$)$ Next: count the number of even integers and display the count.

e$)$ Next: calculate the sum of the odd integers. The approach is similar to counting: choose a

variable name, initialize it to $0$; when the integer is odd, add the integer to the variable. Display

the sum.

f$)$ Next: calculate the sum of the even integers and display the sum.

g$)$ Finally, ignore all negative numbers which the user inputs. One approach: if the integer is

positive, do all the counting and summing, else do nothing $($that is$,$ you can use an if statement

without an else clause$).$

h$)$ If you have time, try this: print a message if the integer is negative.