a. Normality of the STD. Base

b. Normality of the STD. Acid

c. Wt of pure ASA in grams

d. H of Aspirin

e. % ASA in the sample

A 0.9550 g sample of ASA was dissolved in 40.1 mL of standard NaOH. The excess NaOH was neutralized using 18.1 ml of a standard HCI Note that 1.0 mL of the standard acid is equivalent to 0.0273 g sodium carbonate and 1,0 mL of the standard base is equivalent to 0.1005 g KHP. MW: KHP = 204 22 Na2CO3 = 106.0 ASA = 180.16 ASA + NaOH +H2O OH + NaOH 2 +CH COONa Na acetate Na Na Acetylsalicylate x'ss NaOH + HCI Na salicylate NaCl + H2O A 0.9550 g sample of ASA was dissolved in 40.1 mL of standard NaOH. The excess NaOH was neutralized using 18.1 ml of a standard HCI Note that 1.0 mL of the standard acid is equivalent to 0.0273 g sodium carbonate and 1,0 mL of the standard base is equivalent to 0.1005 g KHP. MW: KHP = 204 22 Na2CO3 = 106.0 ASA = 180.16 ASA + NaOH +H2O OH + NaOH 2 +CH COONa Na acetate Na Na Acetylsalicylate x'ss NaOH + HCI Na salicylate NaCl + H2O