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A parabola has vertex (3,2) and contains the point(-1,14) What is the equation of the function ? Y=2/3(x-3)^2+2 Y=(x-3)^2+2 Y=3/4(x-3)^2+2 y=3(x-3)^2+2

A parabola has vertex (3,2) and contains the point(-1,14) What is the equation of the function ? Y=2/3(x-3)^2+2 Y=(x-3)^2+2 Y=3/4(x-3)^2+2 y=3(x-3)^2+2

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