A parallel plate capacitor consists of two plates, each with dimensions 2 cm x 3 cm, which are 5 mm apart.

a) What charge must be placed on each electrode (plate) to make a uniform electric field strength of 2x10^6 N/C?

b) If a proton is released from rest at the surface of the positive plate, what is the acceleration of the proton as it crosses the gap between the plates through this electric field?

c) Using one dimensional kinematics (delta x = v_i*t + 1/2a_xt²), how long does it take the proton to cross the capacitor?

Equation Sheet for reference:

PHY162 Equation Sheet and Concepts for Exam 2, Ch 20-21 Electricity Constants Electron's Charge: e = 1.60 x 10-"9C Electron mass: 9.11x10-31kg Proton mass: 1.67x10-27kg k = 8.99 x 109 N Eo = 8.85 x 10-12 Cz Nm2 1 electron volt = 1 ev = 1.60x10-19/ Area of sphere: Anr2 Area of disk: nr2 Ch. 20 Electric Force: F = k 191/1921 F1 = F12 + F13 + F14 Electrick Field: E = E = Kq Ecapacitor = EOA Ch. 21 Work: W = -qEd AUF = -W Energy Conservation: KA + UA = KB = UB - -mvA + qVA = 5 mvp + qVB Electric Potential Energy: UE = qoV = k- Electric Potential: V = kq AV capacitor = Ed Capacitance: Q = CAV capacitor C = EDA d Concept List Ch 20 Ch 21 Electrostatics Work (done by electric force) Electric Charges Energy Conservation Conservation of Charge Electric Potential Energy Polarization Electric Potential (and how related to electric field) Charge Separation (of point charge and multiple charges) Coulomb's Law Potential Difference in parallel plate capacitors Electric Force Capacitance, Capacitors, and Energy Storage Electric Field (a point charge and multiple charges) Defibrillator