A particle has a charge of +1.25 \"C and moves from point A to point B, a distance of 0.192 m. The particle experiences a constant electric force, and its motion is along the line of action of the force. The difference between the particle's electric potential energy at A and B is EPEA - EPEB = +8.54E-4 J. Calculate the magnitude of the electric force that acts on the particle. SubmitAnswer Tries 0/4