A piece of chalk $($mainly calcium carbonate$)$ is placed in $250.$ mL of $0\mathrm{.}426$ M HCl$.$

All the CaCO$3$ reacts, releasing carbon dioxide gas and leaving $250.$ mL of a clear solution.

$30\mathrm{.}00$ mL of the solution is pipetted into another flask.

$17\mathrm{.}7$ mL of $0\mathrm{.}0514$ M NaOH is required to titrate the HCl remaining in this $30\mathrm{.}00-$mL portion.

What was the original mass of CaCO$3$ in the piece of chalk?