A pilot flies her route in two straight$-$line $5$egments. The displacement vector A for the first segment has a magnitude of $256km$ and a direction $30\mathrm{.}0$ north of east. The displacement vector B for the second segment has a magnitude of $161km$ and a direction due west. The resultant displacement vector is $R=A+B$ and makes an angle $$ with the direction due east. Using the component method, find $($a$)$ the rnagnitude of $R$ and $($b$)$ the directional angle $.$

$($a$)R=I_{\text{N}\text{u}\text{m}\text{b}\text{e}\text{r}}$

Units

km

$($b$)=$ Number

Unit$5$

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Please explain in details how you got your answer becuase i am really confused