a.) pk1 is not -5.35. b.) it is not K2 = (k3)(k4) c.) pk3 doesnt equal 11.41 d.) pk4 doesn't equal -1.635

Learning Goal: The purpose of the problem is to illustrate the distinction between microscopic and macroscopic equilibrium constants. A concrete example of microscopic and macroscopic equilibrium constants is the dissociation of the amino acid glycine. The structural states of glycine involved in its dissociation are: GH2+=+H3NCH2COOH.;GH=GH+GH=+H3NCH2COO+H2NCH2COOH; and G=H2NCH2COO. The dissociation of glycine is described by two macroscopic equilibria GH2+GH+H+and GHG+H+with macroscopic equilibrium constants K1=[GH2+][GH][H+]and K2=[GH][G][H+] At T=298KpK1=2.35 and pK2=9.78. Note pK=log10K. Part A The two neutral forms of glycine GH and GH are involved in the following equilibria with GH2+: GH2+GH+H+and GH2+GH+H+ with microscopic equilibrium constants k1=[GH2+][GH][H+]and k2=[GH2+][GH][H+]. Note that while the macroscopic equilibrium constant K1 describes the equilibrium between GH2+and both neutral forms of glycine i.e. GH=GH+GH, the microscopic constants k1 and k2 describe the equilibria between GH2+and the individual forms GH and GH. Determine the relationship between K1,k1, and k2. If, pk2=7.70 determine pk1. The two neutral forms of glycine GH and GH are also involved in the following equilibria with G: GHG+H+and GHG+H+ with microscopic equilibrium constants k3=[GH][G][H+] and k4=[GH][G][H+].. Deterine the relationship between K2,k3, and k4. View Available Hint(s) K2=k3k4K2=k4k3K2=k31+k411K2=k3+k4 The microscopic equilibrium constants are not independent. It is easy to show that k1k3=k2k4 pi Part D Using your results from Parts AC, determine pk4