A. Play the animation and observe the electron's motion. Then find the magnitude and direction of the electric field such that the electric force balances the magnetic force and the electron travels straight towards the right. (This is a net force probleml). Once you have found the electric eld magnitude, determine the necessary voltage difference between the vertical deflection plates to produce that electric field. Enter your result in the animation (in the box \"Plate Potential V2\") and run the animation to see what happens. If you are successful. your electron should travel in a straight line at a constant speed. B. Suppose the electron were traveling slower than 2.6533 x 10? ms in the same electric and magnetic fields. Which way would it deflected? Why? Test your answer by entering a smaller value for the \"Accelerating Potential V1" in the animation - this will automatically update the electron's initial speed. Were you correct '? C. Would particles with different charges but traveling at the same speed as the electrons in Part A be deflected by the velocity filter ? Explain. An electron is accelerated from rest under the influence of a potential V1 (not shown). At the origin, the electron enters crossed electric and magnetic fields. The electric field is oriented in the -y direction and is produced by parallel plates with a potential difference equal to V2. The magnetic field is oriented in the -z direction (into screen) and is produced by Helmholtz coils. Inputs Outputs Plate separation 0.06 m Initial velocity 2.6533e+7 m/s Accelerating potential V1 2000 Electric field -1.3333e+5 V/m Plate potential V2 8000 X-position 0.090631 m Magnetic field -0.005 T Y-position 0.00030212 m