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A point light at position p is illuminating a point x on a surface. Explain why the strength of the light is proportional to
A point light at position p is illuminating a point x on a surface. Explain why the strength of the light is proportional to 1/(p-x)2, i.e., inversely proportional to the squared distance between the light and the object. Does this rule is analogous with local light/illumination model? Explain.
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Calculus
Authors: Dale Varberg, Edwin J. Purcell, Steven E. Rigdon
9th edition
131429248, 978-0131429246
