Question
A projectile is launched from a platform 12 feet high with an initial velocity of 72 feet per second, The height h of the projectile
A projectile is launched from a platform 12 feet high with an initial velocity of 72 feet per second, The height h of the projectile at t seconds after launch is given by h = -16t^2 + 72t + 12
How many seconds after launch does the projectile attain maximum height?
What is the maximum height?
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Financial Accounting and Reporting a Global Perspective
Authors: Michel Lebas, Herve Stolowy, Yuan Ding
4th edition
978-1408076866
