A random sample of 322 medical doctors showed that 166 had a solo practice.

(a)

Let p represent the proportion of all medical doctors who have a solo practice. Find a point estimate for p. (Round your answer to three decimal places.)

(b)

Find a 95% confidence interval for p. (Enter your answer in the form: lower limit to upper limit. Include the word "to." Round your numerical values to three decimal places.)

Give a brief explanation of the meaning of the interval.

95% of the confidence intervals created using this method would include the true proportion of medical doctors with solo practices.

5% of the confidence intervals created using this method would include the true proportion of medical doctors with solo practices.

5% of the confidence intervals created using this method would include the sample proportion of medical doctors with solo practices, from their respective samples.

95% of the confidence intervals created using this method would include the sample proportion of medical doctors with solo practices, from their respective samples.

(c)

As a news writer, how would you report the survey results regarding the percentage of medical doctors in solo practice?

Report p along with the margin of error.

Report p.

Report the margin of error.

Report the confidence interval.

What is the margin of error based on a 95% confidence interval? (Round your answer to three decimal places.)