A random sample of 332 medical doctors showed that 168 had a solo practice. USE SALT (a) Let p represent the proportion of all medical doctors who have a solo practice. Find a point estimate for p. (Use 3 decimal places.) (b) Find a 99% confidence interval for p. (Use 3 decimal places.) lower limit upper limit Give a brief explanation of the meaning of the interval. 99% of the all confidence intervals would include the true proportion of physicians with solo practices. 1% of the confidence intervals created using this method would include the true proportion of physicians with solo practices. 99% of the confidence intervals created using this method would include the true proportion of physicians with solo practices. 1% of the all confidence intervals would include the true proportion of physicians with solo practices. (c) As a news writer, how would you report the survey results regarding the percentage of medical doctors in solo practice? O Report along with the margin of error. O Report the confidence interval. O Report the margin of error. O Report What is the margin of error based on a 99% confidence interval? (Use 3 decimal places.)