A random sample of 334 medical doctors showed that 176 had a solo practice. I USE SALT (a) Let p represent the proportion of all medical doctors who have a solo practice. Find a point estimate for p. (Use 3 decimal places.) Iv (b) Find a 98% confidence interval for p. (Use 3 decimal places.) lower limit upper limit Give a brief explanation of the meaning of the interval. 0 98% of the condence intervals created using this method would include the true proportion of physicians with solo practices. O 98% of the all condence intervals would include the true proportion of physicians with solo practices. 0 2% of the confidence intervals created using this method would include the true proportion of physicians with solo practices. 0 2% of the all confidence intervals would include the true proportion of physicians with solo practices. (c) As a news writer, how would you report the survey results regarding the percentage of medical doctors in solo practice? 0 Report the margin of error. Q Reportf) along with the margin of error. 0 Report the condence interval. 0 Report 1'). What is the margin of error based on a 98% condence interval? (Use 3 decimal places.)