A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.05 hours, with a standard deviation of 2.43 hours. A random sample of 40 adults with children under the age of 18 results in a mean daily leisure time of 4.24 hours, with a standard deviation of 1.72 hours. Construct and interpret a 90% confidence interval for the mean difference in leisure time between adults with no children and adults with children (H1-H2). Let py represent the mean leisure hours of adults with no children under the age of 18 and represent the mean leisure hours of adults with children under the age of 18. The 90% confidence interval for (44 - H2) is the range from hours to hours. (Round to two decimal places as needed.)

A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5 05 hours, with a standard deviation of 243 hours. A random sample of 40 adults with children under the age of 18 results in a mean daily leisure time of 4.24 hours, with a standard deviation of 1.72 hours. Construct and interpret a 9%% confidence interval for the mean difference in leisure time between adults with no children and adults with children (#1 - P2) Lol pe represent the muan leisure hours of adults with no children under the age of 18 and p, represent the moan luisur hours of actualis with children under the age of 18. The 90% confidence interval for (My - #2) is the range from |_hours to | |hours. (Round to two decimal places as nooded.)