A regression analysis yields the following information:

$Y=2\mathrm{.}21+1\mathrm{.}49x$;$n=10$;$sy.x=1\mathrm{.}66$;${\displaystyle \underset{?}{\overset{?}{}}}x=3\mathrm{.}2$;${\displaystyle \underset{?}{\overset{?}{}}}{x}^2=134$;${\displaystyle \underset{?}{\overset{?}{}}}(x-x{)}^2=31\mathrm{.}6$

Compute the $95\%$ confidence interval when $x=4.$

$0\mathrm{.}0,4\mathrm{.}05$

$4\mathrm{.}12,12\mathrm{.}22$

$2\mathrm{.}67,5\mathrm{.}33$

$6\mathrm{.}84,9\mathrm{.}50$