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A regression of length of eruption ( y ) for Old Faithful on the waiting time between eruptions ( x ) yields y ^ =?1.874+0.0753
A regression of length of eruption (y) for Old Faithful on the waiting time between eruptions (x) yields
y^ =?1.874+0.0753x. The output, at right, from R gives the 95% confidence interval for the mean response whenx0= 80 s.
- a)(1) From the output, what is the value ofse(?^y)?
- b)(1) From the output, what is the value of MSE?
- c)(2) Determine the standard error for predicting a neweruption whenx0= 80 s, that isse(y^).
- d)(3) Determine the 95%predictioninterval for a new eruption withx0= 80 s. Hint: the degrees of freedom is the same as from the R output.
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