A researcher compares two compounds (1 and 2) used in the manufacture of car tires that are designed to reduce braking distances for SUVs equipped with the tires. SUVs equipped with tires using compound 1 have a mean braking distance of 54

54 feet and a standard deviation of 6.7

6.7 feet. SUVs equipped with tires using compound 2 have a mean braking distance of 62

62 feet and a standard deviation of 14.9

14.9 feet. Suppose that a sample of 62

62 braking tests are performed for each compound. Using these results, test the claim that the braking distance for SUVs equipped with tires using compound 1 is shorter than the braking distance when compound 2 is used. Let

1

1 be the true mean braking distance corresponding to compound 1 and

2

2 be the true mean braking distance corresponding to compound 2. Use the 0.1

0.1 level of significance.

Step2of4:Compute the value of the test statistic. Round your answer to two decimal places.

Step 3 of 4: Determine the decision rule of rejecting the null hypothesis Ho... round 3 decimal places

Step 4 of 4: Make a decision for the hypothesis test