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A rock is thrown from a cliff top at 18 m/s, 25 degrees above the horizontal. It lands on the beach 4.2 seconds later.
A rock is thrown from a cliff top at 18 m/s, 25 degrees above the horizontal. It lands on the beach 4.2 seconds later. a) What is the height of the cliff? b) How far from the base of the cliff did the rock land?
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To solve this problem we can analyze the motion of the rock in the horizontal and vertical directions separately using the equations of motion a To find the height of the cliff we will use the vertical motion equation h vi t 05 a t2 Where h height of the cliff vi initial vertical velocity 18 ms sin25 t time taken for the rock to land 42 seconds a acceleration due to gravity 981 ms2 taking downward direction ...
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University Physics With Modern Physics
Authors: Wolfgang Bauer, Gary Westfall
2nd edition
73513881, 978-0073513881
