A sample of 28 weekly donntimes (in hours) for a computer produced a variance of 4.488. The nullhypothesis is that the variance of all dann-times for this type computer is equal to 5.Assume that the population is normally distributed and significance level is 5% Then, the value ofchi-square Test statistic and the values of critical values of chi-square are respectively:a) (24.235) and (14.573 and 43.195)b) (17.602) and (13.844 and 41.923)c) (28.193) and (15.308 and 44.461)d) (31.784) and (12.879 and 40.113)