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A sigma antibonding MO is taken as the difference of two hydrogen is AOs, (1)=N[sA(1)sB(1)] N, for this antibonding sigma orbital. Express your answer in

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A sigma antibonding MO is taken as the difference of two hydrogen is AOs, (1)=N[sA(1)sB(1)] N, for this antibonding sigma orbital. Express your answer in terms of the overlap integral, S. Step 1 of 4 What is the probability conditional check for this function to be normalized? (1)(1)d=2(1)(1)d=12(1)d=2(1)d=02(1)d=12(1)d=0 Expand the integral. (1)(1)d=N2[sA(1)sA(1)]d+N2[sA(1)sB(1)]d+N2[sB(1)sA(1)]dN2[sB(1)sB(1)]dN[sA(1)sA(1)]dN[sA(1)sB(1)]dN[sB(1)sA(1)]d+N[sB(1)sB(1)]dN[sA(1)sA(1)]d+N[sA(1)sB(1)]d+N[sB(1)sA(1)]dN[sB(1)sB(1)]dN2[sA(1)sA(1)]dN2[sA(1)sB(1)]dN2[sB(1)sA(1)]d+N2[sB(1)sB(1)]d Evaluate the integral. (Use the following as necessary: the overlap integral S,, and .) N2[sA(1)sA(1)]d=N2([)N2[sA(1)sB(1)]d=N2(N2[sB(1)sA(1)]d=N2()N2[sB(1)sB(1)]d=N2( Therefore, (1)(1)d=1 A sigma antibonding MO is taken as the difference of two hydrogen is AOs, (1)=N[sA(1)sB(1)] N, for this antibonding sigma orbital. Express your answer in terms of the overlap integral, S. Step 1 of 4 What is the probability conditional check for this function to be normalized? (1)(1)d=2(1)(1)d=12(1)d=2(1)d=02(1)d=12(1)d=0 Expand the integral. (1)(1)d=N2[sA(1)sA(1)]d+N2[sA(1)sB(1)]d+N2[sB(1)sA(1)]dN2[sB(1)sB(1)]dN[sA(1)sA(1)]dN[sA(1)sB(1)]dN[sB(1)sA(1)]d+N[sB(1)sB(1)]dN[sA(1)sA(1)]d+N[sA(1)sB(1)]d+N[sB(1)sA(1)]dN[sB(1)sB(1)]dN2[sA(1)sA(1)]dN2[sA(1)sB(1)]dN2[sB(1)sA(1)]d+N2[sB(1)sB(1)]d Evaluate the integral. (Use the following as necessary: the overlap integral S,, and .) N2[sA(1)sA(1)]d=N2([)N2[sA(1)sB(1)]d=N2(N2[sB(1)sA(1)]d=N2()N2[sB(1)sB(1)]d=N2( Therefore, (1)(1)d=1

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