A simultaneous dehydration reaction of liquid 2-methyl-2-butanol (A) produces 2-methyl-2- butene (B) and 2-methyl-1-butene (C) as shown in Figure 1 was carried out in a two continuous stirred tank reactor (CSTR) connected in series. The dehydration of A to B occur in second order whereas dehydration to C was in first order. CH ki CH-CH=CH-CH 2-methyl-2-butene (B) CH,--CH-CH CH k OH 2-methyl-2-butanol(A) -CH=CH-CH-CH 2-methyl-1-butene(C) Figure 1 Dehydration reaction of liquid 2-methyl-2-butanol CH a) Inlet stream consists of pure A with concentration of 40 mol.dm and constant volumetric flowrate of 2 mmin-1. The concentration of A at the exit stream of reactor one was reduced to 50%. The composition of product leaving reactor one consists of 60% B and 40% C. If the size of reactor one is 5 m and reactor two is double of reactor one, determine the composition of remaining A, product B and C in the exit stream of reactor two. (24 marks) b) Determine the yield of 2-methyl-2-butene (B) from reactor two. (3 marks) CONFIDENTIAL APPENDIX 1(1) ARRHENIUS LAW k = AeE/RT in = J kg E In IDEAL GAS CONSTANT dm.atm m.am R = 0.082 = 0,082 mol. K kmol. cal 1.987 mol-K = 8.314 mol. K ENERGY BALANCE - 1. - Fo ur -T.) Fox{akt: +40 (0 ") = 0 -FR ADIABTIC TEMPERATURE x[-AHpxCr)] + Tie + XACT: TE C + XC. EQUILIBRIUM CONVERSION XER = 2.C:(T-T.) -AHRXTB) + AC (T-T:) NUMERICAL METHODS Trapezoidal rule *FCx) dx = {1FX.) + f(x)] f() Simpson's one-third rule Lax = $1sx) + 45(X.) + F(X2) Simpson's three-eighths rule wax =als(x) + 35(x)+31(x)) +5%)] * r. dX = +3fX) (X:)] CONFIDENTIAL APPENDIX 1(2) Five-point quadrature formula * F(x) dx = $rx.) + 4f(x) + 2F(X.) + 4f(X.) +F(X)] Integrals dx = In: dx (1-x) 1 1 1-X 1-X dx x Site == n1 ) dx 1 + =-In(1 + Ex) *(1 + ex) dx (1 + 2)2x (1-x) = 22(1 + 8) In(1 x) + e*x+ (1-x) Differentiation = deler(x) = cf'(x) a F()g(x)] = f(x)g'(x) + f(x)9(x) g(x)}'(x) f(x)g'(x) 19(x) al caras d f(x) dx 9(x)