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A slow moving particle is captured by a deuteron (d) and this reaction produces two neutrons (n) in the final state, i.e., n+d n
A slow moving particle is captured by a deuteron (d) and this reaction produces two neutrons (n) in the final state, i.e., n+d n + 1. Neutron and deuteron have even intrinsic parities, whereas 7 has odd intrinsic parity. L and S are the orbital and spin angular momenta, respectively of the system of two neutrons. Which of the following statements regarding the final two-neutron state is(are) CORRECT? It has odd parity L+S is odd L-1. S-1 L=2, S=0
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Introductory Classical Mechanics
Authors: David Morin
1st edition
9780511808951, 521876222, 978-0521876223
